UNIT 01: SOLUTION PREVIOUS YEAR QESTIONS CBSE BOARD
Mass Percentage, Mole Fraction, Molarity, Molality
MCQ
1. Assertion (A): Molality of a solution in liquid state changes with temperature.
Reason (R): The volume of solution changes with the change in temperature.
(a) Both Assertion (A) and Reason (R) are correct statements, and Reason (R) is the correct explanation of Assertion (A).
(b) Both Assertion (A) and Reason (R) are correct statements, but Reason (R) is not the correct explanation of Assertion (A).
(c) Assertion (A) is correct, but Reason (R) is incorrect statement.
(d) Assertion (A) is incorrect, but Reason (R) is correct statement. (2020)
2. 50 mL of an aqueous solution of glucose C6H12O6 (Molar mass: 180 g/mol) contains 6.02 x 1022 molecules. The concentration of the solution will be
(a) 0.1 M
(b) 0.2 M
(c) 1.0 M
(d) 2.0 M (2020)
VSA (1 mark)
3. Define the following term: Molality (m) (NCERT, 1/2, Delhi 2017)
4. Define the following term: Molarity (M) (NCERT, 1/2, Delhi 2017)
Solubility of Gas in a Liquid (Henry's Law)
MCQ
5. The value of Henry's constant KH is
(a) greater for gases with higher solubility
(b) greater for gases with lower solubility
(c) constant for all gases
(d) not related to the solubility of gases. (2025)
6. Value of Henry's constant KH
(a) increases with decrease in temperature
(b) decreases with increase in temperature
(c) increases with increase in temperature
(d) remains constant. (2023)
7. On dissolving ammonium chloride in water at room temperature, the solution feels cool to touch. Under which of the following conditions does salt dissolve faster?
(a) Powdered salt in cold water
(b) Powdered salt in hot water
(c) Salt crystals in cold water
(d) Salt crystals in hot water (2023)
8. Low concentration of oxygen in the blood and tissues of people living at high altitude is due to
(a) high atmospheric pressure
(b) low temperature
(c) low atmospheric pressure
(d) both low temperature and high atmospheric pressure. (2023)
9. An unknown gas 'X' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of 'X' gas when the pressure of gas is doubled at the same temperature is
(a) 0.08
(b) 0.04
(c) 0.02
(d) 0.92 (Term I, 2021-22)
VSA (1 mark)
10. Why aquatic animals are more comfortable in cold water than in warm water? (1/3, 2018)
11. Gas (A) is more soluble in water than gas (B) at the same temperature. Which one of the two gases will have the higher value of K₁ (Henry's constant) and why? (1/2, 2016)
SAI (2 marks)
12. State Henry's law. Why are aquatic species more comfortable in cold water as compared to warm water? (2025)
13. What is Henry's law? Give one application of it. (2023)
14. State Henry's law and mention two of its important applications. (2020)
15. State Henry's law. Why is air diluted with helium in the tanks used by scuba divers? (2/5, 2020)
16. State Henry's law. Calculate the solubility of CO2 in water at 298 K under 760 mm Hg.
(KH for CO2 in water at 298 K is 1.25 x 106 mm Hg) (2020)
17. Give reasons for the following.
(a) Aquatic species are more comfortable in cold water than in warm water.
(b) At higher altitudes people suffer from anoxia resulting in inability to think. (Al 2019)
SA II (3 marks)
18. Henry's law constant for CO2 in water is 1.67 × 108 Pa at 298 K. Calculate the number of moles of CO₂ in 500 mL of soda water when packed under 2.53 x 105 Pa at the same temperature. (2025)
1.4 Vapour Pressure of Liquid Solutions
Raoult's Law
MCQ
19. Which of the following formula represents Raoult's law for a solution containing non-volatile solute?
(a) psolute = . Xsolute
(b) p= KH. X
(c) ptotal = psolvent
(d) psolute = . Xsolvent (Term I, 2021-22)
VSA (1 mark)
20. Identify which liquid will have a higher vapour pressure at 90 °C if the boiling points of two liquids A and B are 140 °C and 180 °C, respectively. (One word, 2020)
SAI (2 marks)
21. State Raoult's law for a solution containing volatile components. Why is the vapour pressure of an aqueous solution of glucose lower than that of water?(2025)
22. State Raoult's law for a solution containing volatile components. What is the similarity between Raoult's law and Henry's law? (2020)
Ideal and Non-ideal Solutions
MCQ
23. A solution of acetone in chloroform
(a) obeys Raoult's law
(b) forms azeotrope
(c) shows a positive deviation from Raoult's law
(d) shows a negative deviation from Raoult's law. (2025)
24. A solution of acetone in ethanol
(a) obeys Raoult's law
(b) forms an ideal solution
(c) shows a positive deviation from Raoult's law
(d) shows a negative deviation from Raoult's law.(2025)
25. An azeotropic solution of two liquids has a boiling point lower than either of the two when it
(a) shows a positive deviation from Raoult's law
(b) shows a negative deviation from Raoult's law
(c) shows no deviation from Raoult's law
(d) is saturated. (2024, Term I, 2021-22)
26. Which one of the following pairs will form an ideal solution?
(a) Chloroform and acetone
(b) Ethanol and acetone
(c) n-Hexane and n-heptane
(d) Phenol and aniline (Term 1, 2021-22)
27. On mixing 20 mL of acetone with 30 mL of chloroform, the total volume of the solution is
(a) < 50 mL
(b) = 50 mL
(c) > 50 mL
(d) = 10 mL (Term I, 2021-22)
VSA(1 mark)
28. What happens when acetone is added to pure ethanol? (1/2, 2020)
29. Define the following term: Ideal solution. (1/2, Delhi 2017, 1/5, Al 2017 C)
30. In non-ideal solution, what type of deviation shows the formation of maximum boiling azeotropes? (1/2, Al 2016)
SAI (2 marks)
31. Give reasons:
(a) Cooking is faster in pressure cooker than in an open pan.
(b) On mixing liquid X and liquid Y, volume of the resulting solution decreases. What type of deviation from Raoult's law is shown by the resulting solution? What change in temperature would you observe after mixing liquids X and Y? (2025)
32. Define Azeotrope. What type of Azeotrope is formed by negative deviation from Raoult's law? Give an example. (2025)
33. The vapour pressure of pure liquid X and pure liquid Y at 25 °C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution. (2023)
34. What type of deviation from Raoult's law is observed by mixing chloroform and acetone? Why is a decrease in a vapour pressure observed in mixing chloroform and acetone? (2021)
35. Write two differences between ideal solutions and non-ideal solutions.(2/3, 2020 C, Delhi 2019, 2/5, Al 2017)
36. What type of azeotropic mixture will be formed by a solution of acetone and chloroform? Justify on the basis of strength of intermolecular interactions that develop in the solution. (Al 2019)
SA II (3 marks)
37. (a) Differentiate between Ideal solution and non-ideal solution.
(b) 30 g of urea is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg. (2023)
CBQ (4 marks)
38. Read the following passage carefully and answer the questions that follow:
According to the generally accepted definition of the ideal solution there are equal interaction forces acting between molecules belonging to the same or different species. (This is equivalent to the statement that the activity of the components equals the concentration.) Strictly speaking, this condition is fulfilled only in exceptional cases for mixtures (optical isomers, isotopic mixtures of an element, hydrocarbon mixtures). It is still usual to talk about ideal solutions as limiting cases in reality since very dilute solutions behave ideally with respect to the solvent. This view is further supported by the fact that Raoult's law empirically found for describing the behaviour of the solvent in dilute solutions can be deduced thermodynamically via the assumption of ideal behaviour of the solvent.
(a) Give one example of miscible liquid pair which shows negative deviation from Raoult's law. What is the reason for such deviation?
(b) (i) State Raoult's law for a solution containing volatile components.
OR
(b) (ii) Raoult's law is a special case of Henry's law. Comment.
(c) Write two characteristics of an ideal solution. (2025)
39. Read the following passage carefully and answer the questions that follow:
Raoult's law for volatile liquids states that the partial vapour pressure of each component in the solution is directly proportional to its mole fraction, whereas for a non-volatile solute, it states that the vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction. Two liquids A and B are mixed with each other to form a solution, the vapour phase consists of both components of the solution. Once the components in the solution have reached equilibrium, the total vapour pressure of the solution can be determined by combining Raoult's law with Dalton's law of partial pressures. If a non-volatile solute B is dissolved into a solvent A to form a solution, the vapour pressure of the solution will be lower than that of the pure solvent. The solutions which obey Raoult's law over the entire range of concentration are ideal solutions, whereas the solutions for which vapour pressure is either higher or lower than that predicted by Raoult's law are called non-ideal solutions. Non-ideal solutions are identified by determining the strength of the intermolecular forces between the different molecules in that particular solution. They can either show positive or negative deviation from Raoult's law depending on whether the A-B interactions in solution are stronger or weaker than A-A and B-B interactions.
(a) 20 mL of a liquid A was mixed with 20 mL of liquid B. The volume of resulting solution was found to be less than 40 mL. What do you conclude from the above data?
(b) Which of the following show positive deviation from Raoult's law? Carbon disulphide and Acetone; Phenol and Aniline; Ethanol and Acetone
(c) The vapour pressure of a solution of glucose in water is 750 mm Hg at 100°C. Calculate the mole fraction of solute. (Vapour pressure of water at 373 K = 760 mm Hg)
OR
(c) The boiling point of solution increases when 1 mol of NaCl is added to 1 litre of water while addition of 1 mol of methanol to one litre of water decreases its boiling point. Explain the above observations. (2023)
Relative Lowering in Vapour Pressure
MCQ
40. The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0-0225. The mole fraction of the non-volatile solute is
(a) 0.80
(b) 0.725
(c) 0.15
(d) 0.0225 (2024)
VSA (1 mark)
41. Define the following term:
Colligative properties (1/2, Delhi 2017)
SAI (2 marks)
42. A solution is prepared by dissolving 10 g of non-volatile solute in 200 g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308 K = 32 mm Hg) (2023)
SA II (3 marks)
43. Vapour pressure of water at 293 K is 17.536mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol¹) is dissolved in 500 g of water. (2021)
44. 30 g of urea (M = 60 g mol¹) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg. (3/5, Al 2017)
LA (5 marks)
45. (a) State Henry's law and mention its two applications.
(b) 5% aqueous solution of a non-volatile solute was made and its vapour pressure at 373 K was found to be 745 mm. Vapour pressure of pure water at this temperature was 760 mm. Calculate the molar mass of solute. (2020 C)
Elevation of Boiling Point
MCQ
46. The boiling point of a 0.2 m solution of a non-electrolyte in water is (K, for water = 0.52 K kg mol¯¹)
(a) 100 °C
(b) 100.52 °C
(c) 100.104 °C
(d) 100.26 °C (Term I, 2021-22)
47. Assertion (A): Elevation in boiling point is a colligative property.
Reason (R): Elevation in boiling point is directly proportional to molarity.
(a) Both Assertion (A) and Reason (R) are correct statements, and Reason (R) is the correct explanation of the Assertion (A).
(b) Both Assertion (A) and Reason (R) are correct statements, but Reason (R) is not the correct explanation of the Assertion (A).
(c) Assertion (A) is correct, but Reason (R) is wrong statement.
(d) Assertion (A) is wrong, but Reason (R) is correct statement. (2020)
CBQ(4 marks)
48. Read the following passage carefully and answer S the questions that follow:
The cause for deviation from Raoult's law in the colligative properties of non-ideal solutions lie in the nature of interactions at the molecular level. These properties show deviations from Raoult's law due to difference in interactions between solute - solvent, solute - solute and solvent - solvent. Some liquids on mixing, form azeotropes which are binary mixtures having the same composition in liquid and vapour phase and boil at a constant temperature. In such cases, it is not possible to separate the components by fractional distillation. There are two types of azeotropes called minimum boiling azeotrope and maximum boiling azeotrope.
(a) Pure ethanol cannot be prepared by fractional distillation of ethanol-water mixture. Comment.
(b) Why does a mixture of chloroform and acetone show deviation from ideal behaviour?
(c) (i) The vapour pressure of pure benzene at a certain temperature is 1.25 atm. When 1.2 g of non-volatile, non-electrolyte solute is added to 60 g of benzene (M = 78 g mol-¹), the vapour pressure of the solution becomes 1.237 atm. Calculate the molar mass of the non-volatile solute.
OR
(c) (ii) The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K for benzene is 2.53 K kg mol-¹. (2024)
LA (5 marks)
49. (i) Boiling point of water at 750 mm Hg pressure is 99.68 °C. How much sucrose (Molar mass = 342 g mol¹) is to be added to 500 g of water such that it boils at 100 °C? (K for water = 0.52 K kg mol-¹)
(ii) State Henry's law and write its any one application.(2024)
Depression of Freezing Point
MCQ
50. In the following diagram point 'X' represents
(a) boiling point of solution
(b) freezing point of solvent
(c) boiling point of solvent
(d) freezing point of solution. (Term I, 2021-22)
SA I (2 marks)
51. A solution containing 60 g of a non-volatile solute in 250 g of water freezes at 270.67 K. Calculate the molar mass of the solute. (Kf, of water = 1.86 K kg mol¯¹) (2024)
52. Nisha took two aqueous solutions one containing 7.5 g of urea (Molar mass = 60 g/mol) and the other containing 42.75 g of substance Z in 100 g of water, respectively. It was observed that both the solutions froze at the same temperature. Calculate the molar mass of Z. (2020)
53. Calculate the freezing point of a solution containing 60 g of glucose (molar mass = 180 g mol-¹) in 250 g of water. (Kf, of water = 1.86 K kg mol-¹) (2018)
SA II (3 marks)
54. Vapour pressure of pure water at 298 K is 24.8 mm Hg. Calculate the lowering in vapour pressure of an aqueous solution which freezes at -0.3°C. (Kf, of water1.86 K kg mol-¹) (2025)
55. A solution of glucose (molar mass = 180 g mol-¹) in water has a boiling point of 100.20 °C. Calculate the freezing point of the same solution. Molal constants for water Kf and Kb are 1.86 K kg mol-¹ and 0.512 K kg mol-¹ respectively. (2025)
56. An antifreeze solution is prepared by dissolving 31 g of ethylene glycol (Molar mass = 62 g mol-¹) in 600 g of water. Calculate the freezing point of the solution. (Kf, for water = 1.86 K kg mol-¹) (2020)
57. Calculate the mass of ascorbic acid (Molar mass 176 g mol-¹) to be dissolved in 75 g of acetic acid, to lower its freezing point by 1.5 0 C (K, 3.9 K kg mol-¹) (NCERT Intext, 2020)
58. 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol-¹. Find the molar mass of the solute. (3/5, Delhi 2019)
59. A 5% solution (by mass) of cane-sugar in water has freezing point of 271 K. Calculate the freezing point of 5% solution (by mass) of glucose in water if the freezing point of pure water is 273.15 K. [Molecular masses: Glucose C6H12O6: 180; Cane-sugar C12H22O11 : 342] (NCERT, 3/5 Delhi 2019)
60. A 4% solution (w / w) of sucrose ( M = 342g mol-¹ ) in water has a freezing point of 271.15 K. Calculate the freezing point of 5% glucose (M = 180 g mol-¹) in water. (Given: Freezing point of pure water = 273.15K )(Delhi 2019)
61. A 10% solution (by mass) of sucrose in water has freezing point of 269.15 K. Calculate the freezing point of 10% glucose in water, if freezing point of pure water is 273.15 K. (Given: Molar mass of sucrose = 342 g mol-¹, molar mass of glucose = 180g mol-¹) (Delhi 2017)
LA (5 marks)
62. (i) Ishan's automobile radiator is filled with 1.0 kg of water. How many grams of ethylene glycol (Molar mass = 62 g mol-¹) must Ishan add to get the freezing point of the solution lowered to - 2.8 0C ? (Kf, for water is 1.86 K kg mol-¹)
(ii) What type of deviation from Raoult's law is shown by ethanol and acetone mixture? Give reason. (2024)
Osmosis and Osmotic Pressure
MCQ
63. An unripe mango placed in a concentrated salt solution to prepare pickle, shrivels because
(a) it gains water due to osmosis
(b) it loses water due to reverse osmosis
(c) it gains water due to reverse osmosis
(d) it loses water due to osmosis (2025)
64. Isotonic solutions have the same
(a) density
(b) refractive index
(c) osmotic pressure
(d) volume. (2024)
65. The colligative property used for the determination of molar mass of polymers and proteins is
(a) osmotic pressure
(b) depression in freezing point
(c) relative lowering in vapour pressure
(d) elevation in boiling point. (2023)
66. Assertion (A): A raw mango placed in saline solution loses water and shrivel into pickle.
Reason (R): Through the process of reverse osmosis raw mango shrivel into pickle.
(a) Both Assertion (A) and Reason (R) are correct statements, and Reason (R) is the correct explanation of the Assertion (A).
(b) Both Assertion (A) and Reason (R) are correct statements, but Reason (R) is not the correct explanation of the Assertion (A).
(c) Assertion (A) is correct, but Reason (R) is incorrect statement.
(d) Assertion (A) is incorrect, but Reason (R) is correct statement. (Term I, 2021-22)
57. Assertion (A): Osmotic pressure is a colligative property.
Reason (R): Osmotic pressure is directly proportional to molarity.
(a) Both Assertion (A) and Reason (R) are correct statements, and Reason (R) is the correct explanation of the Assertion (A).
(b) Both Assertion (A) and Reason (R) are correct statements, but Reason (R) is not the correct explanation of the Assertion (A).
(c) Assertion (A) is correct, but Reason (R) is incorrect statement.
(d) Assertion (A) is incorrect, but Reason (R) is correct statement, (2020)
VSA (1 mark)
68. What happens when a pressure greater than osmotic pressure is applied on the solution side separated from solvent by a semi-permeable membrane? (1/2, 2020)
69. Give reason for the following: Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers. (1/2, 2018)
70. Define the following term : Osmotic pressure (1/5, Al 2017)
SAI (2 marks)
71. Define osmotic pressure. Why is measurement of osmotic pressure method preferred for the determination of molar masses of macromolecules such as proteins and polymers? (2025)
72. A 6% solution of glucose (molar mass = 180 g mol¯¹) is isotonic with 2.5% solution of an unknown organic substance. Calculate the molecular weight of the of the unknown organic substance. (2024)
73. For a 5% solution of urea (Molar mass = 60 g/mol), calculate the osmotic pressure at 300 K. [R = 0.0821 L atm K¯¹ mol-¹](2020)
74. Give reasons:
(a) Cooking is faster in pressure cooker than in cooking pan.
(b) Red blood cells (RBC) shrink when placed in saline water but swell in distilled water. (2019)
75. (i) Out of 1 M glucose and 2 M glucose, which one has a higher boiling point and why?
(ii) What happens when the external pressure applied becomes more than the osmotic pressure of solution? (2/5, Delhi 2016)
76. Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing
(i) 1.2% sodium chloride solution?
(ii) 0.4% sodium chloride solution? (2/5, Delhi 2016)
SA II (3 marks)
77. At 300 K, 30 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of a glucose solution is 1.52 bar at the same temperature, what would be its concentration? (Al 2019)
LA (5 marks)
78. (ⅰ) Define reverse osmosis.
(ii) Why are aquatic species more comfortable in cold water in comparison to warm water?
van't Hoff Factor and Abnormal Molar Mass
MCQ
79. In case of association, abnormal molar mass of solute will
(a) increase
(b) decrease
(c) remain same
(d) first increase and then decrease. (2025)
80. van't Hoff factor for KCI solution assuming the complete dissociation is
(a) 1
(b) 2
(c) 0.5
(d) 1.5(2024)
VSA (1 mark)
81. Define the following term: van't Hoff factor (Delhi 2017)
82. Define the following term: Abnormal molar mass (Delhi 2017)
SAI (2 marks)
83. Predict the state of the solute in the solution in the following situations:
(a) When 'i' is found to be more than one.
(b) When 'i' is found to be less than one. (2020)
van't Hoff Factor and Relative Lowering of Vapour Pressure
SA II (3 marks)
84. The vapour pressure of a solvent at 283 K is 100 mm Hg. Calculate the vapour pressure of a dilute solution containing 1 mole of a strong electrolyte AB in 50 moles of the solvent at 283 K (assuming complete dissociation of solute AB). (2024)
van't Hoff Factor and Elevation of Boiling Point
VSA(1 mark)
85. Give reason for the following:
Elevation of boiling point of 1 M KCI solution is nearly double than that of 1 M sugar solution. (1/2, 2018)
SAI (2 marks)
86. Give reasons:
(i) 0.1 M KCI has higher boiling point than 0.1 M glucose.
(ii) Meat is preserved for a longer time by salting.
SAII (3 marks)
87. Calculate elevation of the boiling point of the solution when 2 g of MgSO4, (molar mass = 120g / mol) was dissolved in 100 g of water, assuming MgSO4 undergoes complete dissociation. (Kf, for water = 0.52 K kg/mol) (2024)
88. Give reasons:
(a) Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers.
(b) Aquatic animals are more comfortable in cold water than in warm water.
(c) Elevation of boiling point of 1 M KCI solution is nearly double than that of 1 M sugar solution. (2023)
89. (a) Out of 0.1 molal aqueous solution of glucose and 0.1 molal aqueous solution of KCI, which one will have higher boiling point and why?
(b) Predict whether van't Hoff factor, (i) is less than one or greater than one in the following:
(i) CH3COOH dissolved in water
(ii) CH3COOH dissolved in benzene (2019)
90. Calculate the boiling point elevation for a solution prepared by adding 10 g of CaCl2, to 200 g of water. (Kf, for water = 0.52 K kg/mol, molar mass of CaCl₂ = 111gmol-1) (3/5, Al 2017)
91. Calculate the boiling point of solution when 4 g of MgSO4 (M = 120g mol-1) was dissolved in 100 g of water, assuming MgSO4, undergoes complete ionization. (Kb for water = 0.52Kkg mol-1) (Al 2016)
LA (5 marks)
92. (i) Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution?
(ii) A non-volatile solute X (molar mass = 50g mol-1) when dissolved in 78 g of benzene reduced its vapour pressure to 90%. Calculate the mass of X dissolved in the solution.
(iii) Calculate the boiling point of elevation for a solution prepared by adding 10 g of MgCl2 to 200 g of water assuming MgCl2, is completely dissociated. (Kb, for water 0.512 K kg mol-1, molar mass MgCl₂ = 95 g mol-1) (2023)
van't Hoff Factor and Depression of Freezing Point
MCQ
93. The freezing point of one molal KCI solution, assuming KCI to be completely dissociated in water, is (Kf, for water = 1.86 K kg mol-1)
(a) - 3.720C
(c) - 1.860C
(b) 3.72 0C
(d) 2.72 0C (2025)
94. Out of the following 1.0 M aqueous solutions which one will show largest freezing point depression?
(a) NaCl
(b) Na2SO4
(c) C6H12O6
(d) Al2(SO4)3 (2023)
SA II (3 marks)
95. When 19.5 g of F-CH2-COOH (molar mass = 78 g mol-¹) is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C. Calculate the degree of dissociation of F-CH2-COOH. [Given: Kf, for water = 1.86 K kg mol-¹] (2023, 3/5, 2020)
96. The freezing point of a solution containing 5 g of benzoic acid (M = 122 g mol-¹) in 35 g of benzene is depressed by 2.94 K. What is the percentage association of benzoic acid if it forms a dimer in solution? (K, for benzene = 4.9 K kg mol-¹) (2020)
97. A 0.01 m aqueous solution of AlCl3 freezes at -0.068 °C. Calculate the percentage of dissociation. [Given: Kf, for water = 1.86 K kg mol¹] (2020)
98. Calculate the freezing point of solution when 1.9 g of MgCl2 (M = 95 g mol-¹) was dissolved in 50 g of water, assuming MgCl₂ undergoes complete ionization. (Kf, for water = 1.86 K kg mol-¹) (Delhi 2016)
99. When 2.56 g of sulphur was dissolved in 100 g of CS2 the freezing point lowered by 0.383 K. Calculate the formula of sulphur (Sx). (Kf, for CS2 = 3.83 K kg mol-¹, atomic mass of sulphur = 32 g mol-¹) (3/5, Delhi 2016)
LA (5 marks)
100. (i) Predict whether van't Hoff factor will be less or greater than one, when ethanoic acid is dissolved in benzene.
(ii) Define ideal solution.
(iii) Calculate the mass of CaCl₂ (molar mass = 111 g mol-¹) to be dissolved in 500 g of water to lower its freezing point by 2K, assuming that CaCl₂ undergoes complete dissociation. (K, for water = 1.86 K kg mol-¹) (2024)
101. (a) Give two differences between ideal and non-ideal solutions.
(b) Calculate the amount of NaCl (M = 58.5 g mol-¹) that must be added to 100 g of water so that freezing point is depressed by 2 K. Kf, for water is 1.86 K/m. (2020)
102. (a) Write two characteristics of non-ideal solution.
(b) 2 g of benzoic acid (C6H5COOH) dissolved in 25 g of benzene shows a depression in freezing point equal to 1.62 K. Molal depression constant for benzene is 4.9 K kg mol-¹. What is the percentage association of acid if it forms dimer in solution? (2019)
van't Hoff Factor and Osmotic Pressure
SAII (3 marks)
103. An aqueous solution of NaOH was made and its molar mass from the measurement of osmotic pressure at 27°C was found to be 25 g mol-¹. Calculate the percentage dissociation of NaOH in this solution. [Atomic mass: Na = 23 u, O = 16 u, H = 1 u] (2025)
104. (a) Find the value of van't Hoff factor for acetic acid in benzene as per the given equation: 2CH3COOH(CH3COOH)2, assuming its complete association.
(b) Osmotic pressure of a solution containing 3.5 g of dissolved protein in 0.05 L of a solution is 0.035 atm at 310 K. Calculate the molar mass of the protein. (R = 0.0821 L atm K-¹ mol-¹) (2023)
105. A solution contains 5.85 g NaCl (Molar mass = 58.5 g mol-¹) per litre of solution. It has an osmotic pressure of 4.75 atm at 27°C. Calculate the degree of dissociation of NaCl in this solution. (Given: R = 0.082 L atm K-¹ mol-1)
106. A solution 0.1 M of Na2SO4 is dissolved to the extent of 95%. What would be its osmotic pressure at 27°C? (R = 0.0821 L atm K-¹ mol-¹) (3/5, 2020)
107. (a) Draw the graph between vapour pressure and temperature and explain the elevation in boiling point of a solvent in solution.
(b) Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 litres of water at 25°C assuming it to be completely dissociated. (Atomic masses : K = 39 u, S = 32 u, O = 16 u) (2019)
LA (5 marks)
108. (i) Why is the value of van't Hoff factor for ethanoic acid in benzene close to 0.5?
(ii) Determine the osmotic pressure of a solution prepared by dissolving 2.32 × 10-2 g of K₂SO₄ in 2 L of solution at 25°C, assuming that K₂SO₄ is completely dissociated.
(iii) When 25.6 g of sulphur 25.6 g of sulphur was dissolved in 1000 g of benzene, the freezing point lowered by 0.512 K. Calculate the formula of sulphur (S). (Kf for benzene = 5.12 K kg mol-¹, Atomic mass of sulphur = 32 g mol-¹) (2023)